[jQuery] Re: why is :first-child selecting sub elements?

Hi Liming,

Just a child combinator rather than a descendant combinator:

$("div[id ^= 'childtest_' ] > :first-child").each(function() {
                                       alert( $(this).attr("id") )

});

--Karl

____________

Karl Swedberg

www.englishrules.com

www.learningjquery.com

On Apr 29, 2009, at 4:14 PM, Liming wrote:

my bad. I was changing it around. It shoudl be

$("div[id ^= 'childtest_' ] :first-child").each(function() {
                                       alert( $(this).attr("id") )

});

On Apr 29, 3:55 pm, MorningZ <morni...@gmail.com> wrote:

I don't understand.. there's no where that you are using ":first-

child" like your subject line says

On Apr 29, 11:43 am, Liming <lmxudot...@gmail.com> wrote:

Hello all, I have a lay out like so

<div id="childtest_toprow">

                <div id="subtest_1">

                        <div id="subtest_1_1"></div>

                        <div id="subtest_1_2"></div>

                </div>

                </div>

                <div id="subtest_2">

                </div>

</div>

I want to select the first child of "childtest_toprow" which is

"subtest_1"

when i do

$("div[id ^= 'childtest_' ] :nth-child(1)").each(function() {

                                        alert( $(this).attr("id") )

});

I get "subtest_1" AND "subest_1_1"

what am I doing wrong?

Thanks

ps: i'm using firefox 3 and IE 7