[jQuery] Re: closure inside ajax method

That *should* get called twice. What does debug() do?
If you put alert() instead of it, it will still be just 1 alert?
Also If you can test it in Firefox with Firebug addon (http://
getfirebug.com/), you should be able to see if
there are actually 2 requests going out correctly (and the response
too).

On Jan 27, 6:53 am, bob <xoxeo...@gmail.com> wrote:
> Hi,
> How can access index i inside of "complete" method?
> The following gives me just the last value of i.
>
> var scripts = ['script1.js', 'script2.js'];
>
> for(var i=0; i<scripts.length; i++){
>
>         jQuery.ajax({
>
>                         dataType: 'script',
>                         url: scripts[i],
>                         complete: function (XMLHttpRequest, textStatus) {
>                                         debug('i = ' + i + '   complete:  textStatus = ' + textStatus);
>
>                         }
>                 });
>
>
>
> }