[jQuery] Re: Set radio buttons in jQuery Dialog

Well, I guess I will answer my own ill-formed question.

I forgot to mention that the code above will not set a radio button to
a selected state.

The only thing that works is to use a set of mutually exclusive
checkbox.

I found code by German Schauger that uses a class on the radio button:

$('.mutuallyexclusive').click(function() {
checkedState = $(this).attr('checked');
$('.mutuallyexclusive:checked').each(function() {
$(this).attr('checked', false);
});
$(this).attr('checked', checkedState);
});

This works very nicely...

On Jun 26, 12:09 pm, pclymer <pc89...@gmail.com> wrote:
> I have a 2radiobuttonsin a jQuery Dialog :
>
> <table>
>    <tr>
>       <td><input id="ArriveTriggerIgnition" name="ArriveTrigger"
> type="radio" value="ignition"/></td><td>Ignition off at Location</td>
>    </tr>
>    <tr>
>      <td><input id="ArriveTriggerIdle" name="ArriveTrigger"
> type="radio" value="idle" /></td><td>Arrive when Idle for</td>
>    <tr>
> </table>
>
> I am setting theradiobutton based on another value before opening
> the dialog:
>
>  if (triggerIgnition == "True") {
>             $("#ArriveTriggerIgnition")[0].checked = true;
>         }
>         else {
>             $("#ArriveTriggerIdle")[0].checked = true;
>         }
>
> I have also tried:
>
>       $("#ArriveTriggerIgnition").attr("checked", true); &  $
> ("#ArriveTriggerIgnition").attr("checked", "checked");
>
> Is there something in the jQuery Dialog that is blocking this or is my
> syntax simply wrong? Thanks!