I corrected the selector as pointed by you..But is still cannot make
anything inside success work..
On Dec 17, 5:18 am, Michael Lawson <mjlaw...@us.ibm.com> wrote:
> Is your selector correct for your success function?
>
> perhaps you meant $("#loading") instead of $("loading") ?
>
> cheers
>
> Michael Lawson
> Development Lead, Global Solutions, ibm.com
> Phone: 1-276-206-8393
> E-mail: mjlaw...@us.ibm.com
>
> 'When seen from outer space, our beautiful blue planet has no national
> boundaries.'
>
> http://www.givesmehope.com/
>
> From: idcoder <idrishlaxmid...@gmail.com>
>
> To: "jQuery (English)" <jquery-en@googlegroups.com>
>
> Date: 12/17/2009 08:15 AM
>
> Subject: [jQuery] ajax
>
> i am trying to submit a form using jquery and ajax. The form gets
> submitted without going to the url through ajax and values are entered
> successfully in DB if all entries are correct and validated. also it
> does not updated the DB if any errors.
>
> here is the javascript
>
> $(document).ready(function(){
>
> $('#regist').submit(function(e) {
>
> $.ajax({
> type: "POST",
> url: "submit1.php",
> data: $('#regist').serialize(),
> dataType: "json",
> success: function(){
> $("loading").append("<img
> id='checkmark' src='images/check.png' />");
>
> }
> });
> return false;
> e.preventDefault();
>
> });
>
> });
>
> But i cannot work out the success event in ajax..anything i insert
> into success event does not work...any help would be
> appreciated..thanks
>
> graycol.gif
> < 1KViewDownload
>
> ecblank.gif
> < 1KViewDownload
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