Wednesday, July 1, 2009

[jQuery] Re: Problem with double submit of and form

i try it know with this code, but the problem with double submit of
the form still exists.
I read that I can have so many $(document).ready(function () { }); I
need.

<a href="#" id="testlink">Show Test</a>
<div id="tpanlegen" style="width: 100%; display: none;">
<form id="teilprojektcreate" action="/test.action" method="post">
<select name="test" id="test" class="textfeld" style="width:
100%;">
<option value="1950">Test 1</option>
<option value="2000">Test 2</option>
</select>
<input id="tpcsubmit" value="Submit" type="submit">
$(document).ready(function () {
$('#tpcsubmit').click(function(e) {
$('#teilprojektcreate').ajaxSubmit({
beforeSubmit: function() {
$('#indicator').show();
},
success: function() {
$('#indicator').hide();
$("#col2_content").effect("slide",{ },2000);
},
timeout: 3000,
target: '#col2_content'

});
return false;
});
});
</script>
</form>
</div>
<script type="text/javascript">
<script type="text/javascript">
$(document).ready(function () {
$('#testlink').bind(
'click',
function(e){
$("#tpanlegen").effect("slide",{ },2000
);
});
});
</script>

</script>
Best Regards
Johannes Geppert

-------------------------------------------------
web:http://www.jgeppert.com
twitter:http://twitter.com/jogep

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