Wednesday, March 16, 2016

Digest for comp.programming.threads@googlegroups.com - 2 updates in 2 topics

Ramine <ramine@1.1>: Mar 15 02:07PM -0700

Hello,
 
 
The mean response time of the M/M/c database servers queue is:
 
R = D + 1/Mu = 0.0001 + 1/10000 = 0.0002 second
 
And the mean reponse time of the M/M/1 Network queue is:
 
R = D + 1/Mu = 0.01 + 1/32 = 0.04125 second
 
And the mean reponse time of the M/M/1 Client queue is:
 
R = D + 1/1.7 = 0.6 + 1/1.7 = 1.2 seconds
 
So the total mean response time of the Network is:
 
0.0002 second of the database servers queue + 0.041 second
of the Network queue + 1.2 second of the Client queue , so
the total mean response time of the network of queues in Tandem
is equal to: 1.241 seconds.
 
 
Thank you,
Amine Moulay Ramdane.
bleachbot <bleachbot@httrack.com>: Mar 15 07:06PM +0100

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