[jQuery] Re: JSON + variable

Well, wow thats nice! Thanks for your answer.
Really awesome, I get an answer!

But I have to use dataType: 'jsonp'. If I use dataType: 'json' the
alert doesn't work.

Oh my god it was so simple and I was thinking about it a million
hours, thank you a lot.

On 3 Feb., 17:25, rnivash <rniv...@gmail.com> wrote:
> Hi mueller,
>
> The response is look like a function call.
>
> /*
> yasearch(
>         {
>         "q": "uboot",
>         "f": ["k"],
>         "r": [["uboote"], ["uboot chat"], ["ubootpc spiel"], ["uboot
> simulation"], ["modell uboot"], ["uboot hamburg"], ["uboot museum"],
> ["atom-uboot"], ["uboot ping"], ["rc uboot"]]
>         }
>         )
>
> */
>
> try this,
>
> function yasearch(a) {
>             alert(a.q);
>
> }
>
>         $(function() {
>             $.ajax({
>                 type: 'GET',
>                 url: 'js.html',
>                 data: "format=json&id=123",
>                 success: function(data) {
>                     eval(data);
>                 },
>                 dataType: 'json'
>             });
>         });
>
> On Feb 3, 5:44 pm, weidc <mueller.juli...@googlemail.com> wrote:
>
> > Hello,
>
> > well i got a problem with using JSON.
>
> > My code looks like this:
>
> > $(function()
> > {
>
> >         $.ajax({
> >                 type:'GET',
> >                 url: url,
> >                 data:"format=json&id=123",
> >                 success:function(data) {
> >                         alert(data); // doesn't work
> >                 },
> >                 dataType:'jsonp'
> >         });
>
> > });
>
> > The URL is an external one.
> > The answer looks something like this:
>
> > yasearch({"q":"uboot","f":["k"],"r":[["uboote"],["uboot chat"],["uboot
> > pc spiel"],["uboot simulation"],["modell uboot"],["uboot hamburg"],
> > ["uboot museum"],["atom-uboot"],["uboot ping"],["rc uboot"]]})
>
> > I always get this error msg in firebug:
> > yasearch is not defined
>
> > I tried to define it in any way but it doesn't seem to work. I use
> > JSON for the first time now and don't know how to get an useable
> > answer.
>
> > I hope someone can help me.