Digest for comp.lang.c++@googlegroups.com - 3 updates in 1 topic

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• Hiding "std" - 3 Updates

Hiding "std"

Christian Gollwitzer <auriocus@gmx.de>: May 31 08:37AM +0200 Am 31.05.15 um 00:46 schrieb Stefan Ram:   > int main() > { int std = 3; > std::cout << std << '\n'; }   I can't find a problem here. In C++, namespaces and variables live in a different domain. This would be different in Python, where a module is actually an object and can be passed around and assigned to. But in C++ there is no way to do such a thing, as in the fictional code below.   namespace mystd=::std; void doitthere(namespace where) { where::cout<<"Something"; }   doitthere(mystd);         Christian

Marcel Mueller <news.5.maazl@spamgourmet.org>: May 31 09:11AM +0200 On 31.05.15 00.46, Stefan Ram wrote:   > int main() > { int std = 3; > std::cout << std << '\n'; }   ::std::cout << std   fixes the name clash.     Marcel

"Öö Tiib" <ootiib@hot.ee>: May 31 05:14AM -0700 On Sunday, 31 May 2015 10:11:34 UTC+3, Marcel Mueller wrote: > > std::cout << std << '\n'; }   > ::std::cout << std   > fixes the name clash.   There are none to fix. That int std can not be considered as class-name-or-namespace-name so it does not participate as one in construction of qualified-id 'std::cout'.   In general such code is useful as a test case for a parser of C++ or as element of obfuscation. It would be lot easier for everybody if the compiler said that the name 'std' is taken already and suggested to use some other for that int.

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