[jQuery] Re: Problem in success function

Hi See ,

i tried like

emailInfo.html(data);


It print fine ,


When i out into condition, there i facing Problem ,

like
for example

var test = emailInfo.html(data);

if(test == 'ACCT'){

emailInfo.html(test);

}else{
emailInfo.html("Somthing bla lbla ");
}

On Wed, Jun 3, 2009 at 4:54 PM, ryan.j <ryan.joyce.uk@googlemail.com> wrote:

it's not working because the value of data isn't "ACCT" or "ACAT".

is the response actually returning anything to data? add ...

alert( "data = " + data);

to your success case.


On Jun 3, 12:03 pm, bharani kumar <bharanikumariyer...@gmail.com>
wrote:

>   $(document).ready(function(){
>     $("#txt_airport_code").keyup(function () {
>         //var getValue = $("#txtUser").attr("value");
>
>         var emailInfo = $("#msg1");
>         var airport_code = "airport_code";
>         $.ajax({
>             type: "POST",
>             data:
> "str="+$("#txt_airport_code").attr("value")+"&code="+airport_code,
>             url: "check.php",
>             beforeSend: function(){
>                 emailInfo.html("Checking Email...");
>             },
>             success: function(data){
>                 if(data == "ACAT"){
>                     emailInfo.html("ACAT Already Exist");
>                 }else if(data == "ACCT"){
>                     emailInfo.html("ACCT Already Exist");
>
>                 }else{
>                     emailInfo.html("Available");
>                 }
>             }
>         });
>     });
>   });
>
> Hi All ,
>
> This my snippet ,
>
> am doing the already exist functionality ,
>
> The above snippet is working fine ,
>
> but the problem is ,,
>
> Always the condition  goes to the Available , am not able to mark out my
> Error spot,
>
> Can u tell me , where i made the mistake ,
>
> Thanks advance

--
Regards
B.S.Bharanikumar
http://php-mysql-jquery.blogspot.com/