[jQuery] Re: json format

Hi ,

var name = 'Peter Wraae Marino';

var data ="name="+name;

$.ajax({

url:  "http://localhost/test/gui/ajax_member.php",

type: "GET",

data: data,

cache: false,

dataType:  "json",

success: function(msg){

alert( msg);

},

error: function( XMLHttpRequest, textStatus, errorThrown ){

var t = "XMLHttpRequest: "+XMLHttpRequest+"\n";

t+= "textStatus: "+textStatus+"\n";

t+= "errorThrown: "+errorThrown+"\n";

alert( t );

}

});

in php file

just echo ur post variable like this

echo $_POST['name'];

Now u can get ur post name into alert pop up

Hope this code u wanted?

On Mon, Jun 1, 2009 at 11:39 AM, Peter Marino <marino.peter@gmail.com> wrote:

Hi jQuery,

I'm very new to the json stuff (so warned)...

when I try the following:

var data =

{

"member" :

{

"name" : "Peter Wraae Marino"

}

}

$.ajax({

url: "http://localhost/test/gui/ajax_member.php",

type: "GET",

data: data,

cache: false,

dataType: "json",

success: function(msg){

alert( msg );

},

error: function( XMLHttpRequest, textStatus, errorThrown ){

var t = "XMLHttpRequest: "+XMLHttpRequest+"\n";

t+= "textStatus: "+textStatus+"\n";

t+= "errorThrown: "+errorThrown+"\n";

alert( t );

}

});

I get an error message saying parsing error, I assume this means my data format is wrong.

but when I see how other people have used json data format then I think the way I did it is right?

can someone help me out here?

regards,

Peter

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