[jQuery] Re: G is undefined

The jQuery example is using data.items because the JSON object it is retrieving is different from yours. Its JSON object is coming from the flickr API.

--Karl

____________

Karl Swedberg

www.englishrules.com

www.learningjquery.com

On Jun 29, 2009, at 1:25 PM, expresso wrote:

Mike thanks a lot.  That is so weird.  I got some ideas from
http://docs.jquery.com/GetJSON and as you can see from the example
it's using data.items.

it's working now.  I just wonder why the jQuery example is using
data.items

On Jun 29, 12:19 pm, "Michael Geary" <m...@mg.to> wrote:

That's right, your JSON is perfectly valid. You can test it at:

www.jsonlint.org

Here's the formatted output from that site, with the image tags elided for

clarity, and comments added showing how you'd access each part of it

directly in JavaScript:

    // Data

    [

        // Data[0]

        {

            // Data[0].ImageTag

            "ImageTag": "..."

        },

        // Data[1]

        {

            // Data[1].ImageTag

            "ImageTag": "..."

        }

    ]

As you can see, what you have is an array of two elements. Each of those

elements is an object with a single property named ImageTag with a string

value.

Now back to your code. This is where it goes wrong:

$.each(Data.items, function(i, item) {...});

"Data" here is the JSON data, and you're trying to get its "items" property

and use it as an array. But there is no "items" property - Data itself is

the array, so you'd use it directly:

$.each(Data, function(i, item) {...});

JSON that would work with your original code using Data.items would look

like this:

    // Data

    {

        // Data.items

        "items": [

            // Data.items[0]

            {

                // Data.items[0].ImageTag

                "ImageTag": "..."

            },

            // Data.items[1]

            {

                // Data.items[1].ImageTag

                "ImageTag": "..."

            }

        ]

    }

BTW, I suggest using variable names that begin with lower case. The upper

case first letter makes people think it's the name of a constructor.

-Mike

From: expresso

some tells me that my original JSON is totally valid with the [ and ]

On Jun 29, 11:03 am, MorningZ <morni...@gmail.com> wrote:

http://en.wikipedia.org/wiki/JSON

will show you what it should look like... notice the

outside symbols

are { ... }, not [ .... ]

again, you should look at this if you are working with .NET

and JSON,

it really takes all this guess work from the equation:

http://james.newtonking.com/pages/json-net.aspx

On Jun 29, 12:01 pm, expresso <dschin...@gmail.com> wrote:

Ok, so what should it be wrapped in or how should I reformat this?

On Jun 29, 10:58 am, MorningZ <morni...@gmail.com> wrote:

Wow, is posting the same thing every 3 mins to bump your topic

annoying....

Anyways,

your results wrapped in [ .... ] signifies an Array, not a JSON

object....  hence ".getJSON" has no idea what to do with it

On Jun 29, 11:53 am, expresso <dschin...@gmail.com> wrote:

So is this valid JSON that jQuery can parse? or do I need an

initial level such as "Images":

[{"Images" :

[{"ImageTag":"&lt;img

src=&quot;http://www.xxx.com/image/473.jpg"

alt=&quot;&quot;&gt;"},{"ImageTag":"&lt;img

src=&quot;http://www.xxx.com/image/4852.jpg"

alt=&quot;&quot;&gt;"} ]]

On Jun 29, 10:37 am, expresso <dschin...@gmail.com> wrote:

Ok, figured out that data.items is undefined. Not sure why

because here's the json my url returns:

[{"ImageTag":"&lt;img

src=&quot;http://www.xxx.com/image/473.jpg"

alt=&quot;&quot;&gt;"},{"ImageTag":"&lt;img

src=&quot;http://www.xxx.com/image/4852.jpg"alt=&quot;&quot;&g

t;"}]

On Jun 29, 10:33 am, expresso <dschin...@gmail.com> wrote:

I get the following error:

G is undefined

init()()jquery-1....2.min.js (line 12)

(?)()()Carousel.aspx

(line 30) I()jquery-1....2.min.js (line 19)

F()()jquery-1....2.min.js (line 19) [Break on this error]

(function(){var l=this,g,y=l.jQuery,p=l.....each

(function(){o.dequeue(this,E)})}});

in jquery-1.3.2.min.js

when I call this method of mine:

    $.getJSON("http://localhost:59396/xxx/xxxHandler.ashx?

action=xxxjson",

        function(Data) {

        $.each(Data.items, function(i, item) {

        alert('got here');

        carousel.add(i,

mycarousel_decodeEntities(item.ImageTag));

                if (i == 3) return false;

            });

        });

I know I can get inside function(Data){ and that

the error

starts at $.each I believe